Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
जवळील | 469 | 37 | 1 | 37.0000 |
भगवान | 137 | 12 | 1 | 12.0000 |
याचे | 639 | 36 | 4 | 9.0000 |
इथे | 168 | 9 | 1 | 9.0000 |
किमान | 91 | 8 | 1 | 8.0000 |
यातील | 174 | 8 | 1 | 8.0000 |
शर्मा | 51 | 8 | 1 | 8.0000 |
प्रकाश | 120 | 8 | 1 | 8.0000 |
फलंदाजी | 83 | 8 | 1 | 8.0000 |
यॉर्क | 78 | 8 | 1 | 8.0000 |
तेव्हापासून | 79 | 8 | 1 | 8.0000 |
याच | 410 | 22 | 3 | 7.3333 |
वरील | 177 | 7 | 1 | 7.0000 |
रक्षण | 66 | 7 | 1 | 7.0000 |
१९३६ | 43 | 7 | 1 | 7.0000 |
धारण | 101 | 14 | 2 | 7.0000 |
संजय | 76 | 7 | 1 | 7.0000 |
जमा | 86 | 7 | 1 | 7.0000 |
एकत्र | 214 | 13 | 2 | 6.5000 |
वन | 216 | 13 | 2 | 6.5000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
आहे | 25035 | 25 | 954 | 0.0262 |
डॉ | 785 | 1 | 32 | 0.0313 |
होते | 6612 | 14 | 364 | 0.0385 |
आहेत | 6905 | 18 | 431 | 0.0418 |
जाते | 2313 | 4 | 85 | 0.0471 |
लागते | 316 | 1 | 19 | 0.0526 |
होती | 2762 | 9 | 150 | 0.0600 |
होता | 3161 | 13 | 196 | 0.0663 |
आढळतात | 249 | 1 | 15 | 0.0667 |
फॉर्म्युला | 143 | 1 | 15 | 0.0667 |
पद्धतीने | 178 | 1 | 14 | 0.0714 |
गोष्टी | 147 | 1 | 13 | 0.0769 |
तासांचा | 74 | 1 | 13 | 0.0769 |
घेण्यासाठी | 92 | 1 | 12 | 0.0833 |
असते | 1867 | 11 | 130 | 0.0846 |
जातात | 889 | 5 | 57 | 0.0877 |
खेळतो | 78 | 1 | 11 | 0.0909 |
जातो | 1185 | 4 | 40 | 0.1000 |
येते | 964 | 5 | 49 | 0.1020 |
करतात | 1066 | 8 | 77 | 0.1039 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II